What is the sum from n=1 to infinity of 1(5/6)^n ?

The sum from n=1 to infinity of 1(5/6)^n is 5

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sum from n=1 to infinity of 1(5/6)^n

n = 1 \sum \infty 1 (\frac{5}{6})^{n}

5

Solution steps

n = 1 \sum \infty 1 \cdot (\frac{5}{6})^{n}

Simplify

= n = 1 \sum \infty (\frac{5}{6})^{n}

n = k \sum \infty (a_{n}) = n = 0 \sum \infty (a_{n}) - a_{0} - a_{1} - \dots a_{k - 1}

= n = 0 \sum \infty (\frac{5}{6})^{n} - (\frac{5}{6})^{0}

n = 0 \sum \infty (\frac{5}{6})^{n} = 6

= 6 - (\frac{5}{6})^{0}

Simplify

= 5

\frac{d}{d x} (\frac{1}{5 x - 2})

k = 1 \sum \infty cos (\frac{1}{k}) - cos (\frac{1}{k + 1})

n = 0 \sum \infty \frac{( 3 ^{n} )}{2}

\int \frac{9}{x ^{2} ( x ^{2} + 25 )} d x

\frac{1}{x}

What is the sum from n=1 to infinity of 1(5/6)^n ?
The sum from n=1 to infinity of 1(5/6)^n is 5