What is the derivative of 3x-1/x ?

The derivative of 3x-1/x is 3+1/(x^2)

What is the first derivative of 3x-1/x ?

The first derivative of 3x-1/x is 3+1/(x^2)

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\frac{d}{d x} (3 x - \frac{1}{x})

3 + \frac{1}{x ^{2}}

Solution steps

\frac{d}{d x} (3 x - \frac{1}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) - \frac{d}{d x} (\frac{1}{x})

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

= 3 - (- \frac{1}{x ^{2}})

Simplify

= 3 + \frac{1}{x ^{2}}

\int_{2}^{6} \frac{x}{x ^{2} + 4 x + 13} d x

f (x) = (2 + 3 x) (6 - 5 x)

x^{2} + 6 x + 8, 0

f (x) = 3 sin (x)

\frac{\partial}{\partial x} (\frac{1}{y})

What is the derivative of 3x-1/x ?
The derivative of 3x-1/x is 3+1/(x^2)
What is the first derivative of 3x-1/x ?
The first derivative of 3x-1/x is 3+1/(x^2)