What is the derivative of sin(x^3+2x-1) ?

The derivative of sin(x^3+2x-1) is cos(x^3+2x-1)(3x^2+2)

What is the first derivative of sin(x^3+2x-1) ?

The first derivative of sin(x^3+2x-1) is cos(x^3+2x-1)(3x^2+2)

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\frac{d}{d x} (sin (x^{3} + 2 x - 1))

cos (x^{3} + 2 x - 1) (3 x^{2} + 2)

Solution steps

\frac{d}{d x} (sin (x^{3} + 2 x - 1))

Apply the chain rule:

cos (x^{3} + 2 x - 1) \frac{d}{d x} (x^{3} + 2 x - 1)

= cos (x^{3} + 2 x - 1) \frac{d}{d x} (x^{3} + 2 x - 1)

\frac{d}{d x} (x^{3} + 2 x - 1) = 3 x^{2} + 2

= cos (x^{3} + 2 x - 1) (3 x^{2} + 2)

\frac{d y}{d t} = 5 y + y^{4}, y (0) = 1

1 - cos^{2} (17 x)

f (x) = 6 x^{2} - 20 x^{3}

\frac{d}{d x} (5 - ∣ x - 2 ∣)

8 - x^{2}, x^{2}, - 3, 3

What is the derivative of sin(x^3+2x-1) ?
The derivative of sin(x^3+2x-1) is cos(x^3+2x-1)(3x^2+2)
What is the first derivative of sin(x^3+2x-1) ?
The first derivative of sin(x^3+2x-1) is cos(x^3+2x-1)(3x^2+2)