What is implicit (dy)/(dx),x=sec(4y) ?

The answer to implicit (dy)/(dx),x=sec(4y) is (dy)/(dx)= 1/(sec(4y)tan(4y)*4)

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implicit (dy)/(dx),x=sec(4y)

implicit derivative

\frac{d y}{d x}, x = sec (4 y)

\frac{d y}{d x} = \frac{1}{sec ( 4 y ) tan ( 4 y ) \cdot 4}

Solution steps

x = sec (4 y)

Treat

y

y (x)

Differentiate both sides:

1 = sec (4 y) tan (4 y) \cdot 4 \frac{d y}{d x}

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{1}{sec ( 4 y ) tan ( 4 y ) \cdot 4}

\frac{d y}{d x} = \frac{1}{sec ( 4 y ) tan ( 4 y ) \cdot 4}

\frac{d}{d x} ((x^{2} + 3) (x^{2} - 2)^{8})

4 sin (x) sin (y) + cos (y) y^{^{'}} = 0

f (x) = 4 x^{2} + 12 x + 5, at (- 1)

\int x^{5} x^{3} + 2 d x

\frac{d}{d x} (\frac{2 - 5 x - x ^{2}}{x ^{2} - 6})

What is implicit (dy)/(dx),x=sec(4y) ?
The answer to implicit (dy)/(dx),x=sec(4y) is (dy)/(dx)= 1/(sec(4y)tan(4y)*4)