What is the derivative of (x^8/(16)) ?

The derivative of (x^8/(16)) is (x^7)/2

What is the first derivative of (x^8/(16)) ?

The first derivative of (x^8/(16)) is (x^7)/2

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\frac{d}{d x} (\frac{x ^{8}}{16})

\frac{x ^{7}}{2}

Solution steps

\frac{d}{d x} (\frac{x ^{8}}{16})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{16} \frac{d}{d x} (x^{8})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{16} \cdot 8 x^{8 - 1}

Simplify

\frac{1}{16} \cdot 8 x^{8 - 1} : \frac{x ^{7}}{2}

= \frac{x ^{7}}{2}

\frac{d}{d t} (\frac{1}{t})

x \to 1 + lim (\frac{x + 2}{x + 1})

\int_{1}^{3} \frac{1}{x ( x + 1 )} d x

\int_{1}^{x^{2}} sin^{2} (t) d t

\frac{\partial}{\partial x} ((x + 3 y)^{3})

What is the derivative of (x^8/(16)) ?
The derivative of (x^8/(16)) is (x^7)/2
What is the first derivative of (x^8/(16)) ?
The first derivative of (x^8/(16)) is (x^7)/2