What is the tangent of f(x)=2+1/x ,(4,2.25) ?

The tangent of f(x)=2+1/x ,(4,2.25) is y=-1/16 x+2.5

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tangent of f(x)=2+1/x ,(4,2.25)

tangent of

f (x) = 2 + \frac{1}{x}, (4, 2.25)

y = - \frac{1}{16} x + 2.5

Solution steps

Find the slope of

f (x) = 2 + \frac{1}{x} : \frac{df ( x )}{d x} = - \frac{1}{x ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{1}{16}

Find the line with slope m=

- \frac{1}{16}

and passing through

(4, 2.25) : y = - \frac{1}{16} x + 2.5

y = - \frac{1}{16} x + 2.5

\int_{- 2}^{2} (x^{3} - 2 x + 3) d x

\int (6 x^{2} y - 2 x) d y

\int_{0}^{1} - 9 (x^{2} + 1) e^{- x} d x

y = (1 + 2 x)^{2}, (1, 9)

\frac{\partial}{\partial x} (arctan (y x))

What is the tangent of f(x)=2+1/x ,(4,2.25) ?
The tangent of f(x)=2+1/x ,(4,2.25) is y=-1/16 x+2.5