What is the tangent of y=-7/2 x^2+5x+5,(-1,-7/2) ?

The tangent of y=-7/2 x^2+5x+5,(-1,-7/2) is y=12x+17/2

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tangent of y=-7/2 x^2+5x+5,(-1,-7/2)

tangent of

y = - \frac{7}{2} x^{2} + 5 x + 5, (- 1, - \frac{7}{2})

y = 12 x + \frac{17}{2}

Solution steps

Find the slope of

y = - \frac{7}{2} x^{2} + 5 x + 5 : \frac{d y}{d x} = - 7 x + 5

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 12

Find the line with slope m=

12

and passing through

(- 1, - \frac{7}{2}) : y = 12 x + \frac{17}{2}

y = 12 x + \frac{17}{2}

\int cos^{3} (x) sin^{- 4} (x) d x

\frac{d y}{d x} = \frac{( x ^{3} )}{y ^{2}}

\int (4 e^{x} - x^{3} + 6 x - 8) d x

\int \frac{x ^{5}}{x ^{6} + 4} d x

n = 0 \sum \infty \frac{1}{4 n + 1}

What is the tangent of y=-7/2 x^2+5x+5,(-1,-7/2) ?
The tangent of y=-7/2 x^2+5x+5,(-1,-7/2) is y=12x+17/2