What is the sum from n=1 to infinity of (4n)/(4n+7) ?

The sum from n=1 to infinity of (4n)/(4n+7) is diverges

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sum from n=1 to infinity of (4n)/(4n+7)

n = 1 \sum \infty \frac{4 n}{4 n + 7}

diverges

Solution steps

n = 1 \sum \infty \frac{4 n}{4 n + 7}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 4 \cdot n = 1 \sum \infty \frac{n}{4 n + 7}

Apply Series Divergence Test:

diverges

= 4 diverges

= diverges

(2 x + 5) (4 x - 5)^{2}

\frac{d}{d x} (ln (x^{s i n (x)}))

\int \frac{1}{x 9 x - 1} d x

\int (\frac{cos ( x )}{sin ( 2 x )}) d x

\frac{x + 1770}{30 ( x + 2 )}

What is the sum from n=1 to infinity of (4n)/(4n+7) ?
The sum from n=1 to infinity of (4n)/(4n+7) is diverges