What is the solution for ((dy)/(dx))=(x+y+7)^2 ?

The solution for ((dy)/(dx))=(x+y+7)^2 is y=tan(x+c_{1})-x-7

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((dy)/(dx))=(x+y+7)^2

(\frac{d y}{d x}) = (x + y + 7)^{2}

y = tan (x + c_{1}) - x - 7

Solution steps

(\frac{d y}{d x}) = (x + y + 7)^{2}

Solve using substitution:

y = tan (x + c_{1}) - x - 7

y = tan (x + c_{1}) - x - 7

- \frac{x 1 - y ^{2}}{y 1 - x ^{2}} = \frac{d y}{d x}

n = 0 \sum \infty \frac{n ^{2} + 1}{n !}

\int sin (3 x) cos (3 x) d x

\frac{d}{d u} (\frac{u - 1}{u + 1})

\frac{d ^{2} y}{d x ^{2}} - \frac{d y}{d x} - 30 y = 0

What is the solution for ((dy)/(dx))=(x+y+7)^2 ?
The solution for ((dy)/(dx))=(x+y+7)^2 is y=tan(x+c_{1})-x-7