What is the integral of 2cos(t)+sec^2(t) ?

The integral of 2cos(t)+sec^2(t) is 2sin(t)+tan(t)+C

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integral of 2cos(t)+sec^2(t)

\int 2 cos (t) + sec^{2} (t) d t

2 sin (t) + tan (t) + C

Solution steps

\int 2 cos (t) + sec^{2} (t) d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 cos (t) d t + \int sec^{2} (t) d t

\int 2 cos (t) d t = 2 sin (t)

\int sec^{2} (t) d t = tan (t)

= 2 sin (t) + tan (t)

Add a constant to the solution

= 2 sin (t) + tan (t) + C

\frac{\partial}{\partial x} (ln ((1 - T) \cdot w \cdot x))

\frac{d y}{d x} + 2 y = 4 x

9 π^{3}

arcsin (2 x)

f (x) = x^{4} - 2 x^{2}, at x = 1

What is the integral of 2cos(t)+sec^2(t) ?
The integral of 2cos(t)+sec^2(t) is 2sin(t)+tan(t)+C