What is the derivative of 7/(x^2-x+2) ?

The derivative of 7/(x^2-x+2) is -(7(2x-1))/((x^2-x+2)^2)

What is the first derivative of 7/(x^2-x+2) ?

The first derivative of 7/(x^2-x+2) is -(7(2x-1))/((x^2-x+2)^2)

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\frac{d}{d x} (\frac{7}{x ^{2} - x + 2})

- \frac{7 ( 2 x - 1 )}{( x ^{2} - x + 2 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{7}{x ^{2} - x + 2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{d}{d x} (\frac{1}{x ^{2} - x + 2})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 7 \frac{d}{d x} ((x^{2} - x + 2)^{- 1})

Apply the chain rule:

- \frac{1}{( x ^{2} - x + 2 ) ^{2}} \frac{d}{d x} (x^{2} - x + 2)

= - \frac{1}{( x ^{2} - x + 2 ) ^{2}} \frac{d}{d x} (x^{2} - x + 2)

\frac{d}{d x} (x^{2} - x + 2) = 2 x - 1

= 7 (- \frac{1}{( x ^{2} - x + 2 ) ^{2}} (2 x - 1))

Simplify

7 (- \frac{1}{( x ^{2} - x + 2 ) ^{2}} (2 x - 1)) : - \frac{7 ( 2 x - 1 )}{( x ^{2} - x + 2 ) ^{2}}

= - \frac{7 ( 2 x - 1 )}{( x ^{2} - x + 2 ) ^{2}}

y^{^{''}} - y^{^{'}} - 6 y = 2 e^{t} - t^{2} - 2 t + 3

\int 20 - 0.1

\frac{d}{d y} (4 e^{2 y} (2 x^{2} + 4 x + 2 y + 1))

\int \frac{( ln ( x ^{3} ) )}{x} d x

x \to \infty lim (\frac{x}{5 x})

What is the derivative of 7/(x^2-x+2) ?
The derivative of 7/(x^2-x+2) is -(7(2x-1))/((x^2-x+2)^2)
What is the first derivative of 7/(x^2-x+2) ?
The first derivative of 7/(x^2-x+2) is -(7(2x-1))/((x^2-x+2)^2)