Solution
Solution
Solution steps
Solve separable ODE:
Graph
Popular Examples
4y^{''}+4y^'+17=0derivative of (x+7/(4x^2e^x))integral of arcsin(4/3 x+5)tangent of (x^3+2)^5,\at x=-1tangent of (\partial)/(\partial x)(56y^4x^6-42y^3x^5)
Frequently Asked Questions (FAQ)
What is the solution for y^'+2y=0,y(0)=1 ?
The solution for y^'+2y=0,y(0)=1 is y=e^{-2t}