What is the solution for y^3-(14x+6)+3xy^2y^'=0 ?

The solution for y^3-(14x+6)+3xy^2y^'=0 is y=\sqrt[3]{6+7x+(c_{1})/x}

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y^3-(14x+6)+3xy^2y^'=0

y^{3} - (14 x + 6) + 3 x y^{2} y^{^{'}} = 0

y = 3 6 + 7 x + \frac{c _{1}}{x}

Solution steps

y^{3} - (14 x + 6) + 3 x y^{2} y^{'} (x) = 0

Solve Bernoulli ODE:

y = 3 6 + 7 x + \frac{c _{1}}{x}

y = 3 6 + 7 x + \frac{c _{1}}{x}

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What is the solution for y^3-(14x+6)+3xy^2y^'=0 ?
The solution for y^3-(14x+6)+3xy^2y^'=0 is y=\sqrt[3]{6+7x+(c_{1})/x}