What is the limit as h approaches 0 of-2x-h+8 ?

The limit as h approaches 0 of-2x-h+8 is -2x+8

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limit as h approaches 0 of-2x-h+8

h \to 0 lim (- 2 x - h + 8)

- 2 x + 8

Solution steps

h \to 0 lim (- 2 x - h + 8)

Plug in the value

h = 0

= - 2 x - 0 + 8

Simplify

= - 2 x + 8

x \to 1 lim (\frac{x + 1}{x ^{3} - 1})

n = 5 \sum \infty \frac{2}{( n ^{2} - 1 )}

\frac{d P}{d t} = P - P^{2}

\frac{d y}{d x} = \frac{3}{x ^{2} y - 8 y}

\frac{\partial}{\partial x} (R (x)^{2} + x^{2} - x)

What is the limit as h approaches 0 of-2x-h+8 ?
The limit as h approaches 0 of-2x-h+8 is -2x+8