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Popular >

y^2y^'+5=x^2

Solution

y^{2} y^{^{'}} + 5 = x^{2}

Solution

y = 3 x^{3} - 15 x + c_{1}

Solution steps

y^{2} y^{'} (x) + 5 = x^{2}

Solve separable ODE:

y = 3 x^{3} - 15 x + c_{1}

y = 3 x^{3} - 15 x + c_{1}

Graph

Popular Examples

integral of (7x-5)/(x^2+16)

\int \frac{7 x - 5}{x ^{2} + 16} d x

tangent of f(x)=6-x^2,\at x=7 tangent of

f (x) = 6 - x^{2}, at x = 7

integral of 1/(tan(x)-1)

\int \frac{1}{tan ( x ) - 1} d x

integral from-5 to 6 of x

\int_{- 5}^{6} x d x

derivative of f(x)=(x^2-1)(1-e^x)derivative of

f (x) = (x^{2} - 1) (1 - e^{x})

Frequently Asked Questions (FAQ)

What is the solution for y^2y^'+5=x^2 ?
The solution for y^2y^'+5=x^2 is y=\sqrt[3]{x^3-15x+c_{1}}