What is (\partial)/(\partial y)(x^2y^2z) ?

The answer to (\partial)/(\partial y)(x^2y^2z) is 2x^2yz

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)(x^2y^2z)

\frac{\partial}{\partial y} (x^{2} y^{2} z)

2 x^{2} yz

Solution steps

\frac{\partial}{\partial y} (x^{2} y^{2} z)

Treat

x, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x^{2} z \frac{\partial}{\partial y} (y^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= x^{2} z \cdot 2 y^{2 - 1}

Simplify

= 2 x^{2} yz

y^{^{'}} + 6 y = t + e^{- 5 t}

\int sin^{4} (x) \cdot cos^{4} (x) d x

\int \frac{sec ^{2} ( ln ( x ) )}{2 x} d x

x \to 1 lim (3 x)

\frac{d x}{d t} + 5 x = cos (2 t)

What is (\partial)/(\partial y)(x^2y^2z) ?
The answer to (\partial)/(\partial y)(x^2y^2z) is 2x^2yz