What is the derivative of 7/(x+4) ?

The derivative of 7/(x+4) is -7/((x+4)^2)

What is the first derivative of 7/(x+4) ?

The first derivative of 7/(x+4) is -7/((x+4)^2)

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\frac{d}{d x} (\frac{7}{x + 4})

- \frac{7}{( x + 4 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{7}{x + 4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{d}{d x} (\frac{1}{x + 4})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 7 \frac{d}{d x} ((x + 4)^{- 1})

Apply the chain rule:

- \frac{1}{( x + 4 ) ^{2}} \frac{d}{d x} (x + 4)

= - \frac{1}{( x + 4 ) ^{2}} \frac{d}{d x} (x + 4)

\frac{d}{d x} (x + 4) = 1

= 7 (- \frac{1}{( x + 4 ) ^{2}} \cdot 1)

Simplify

7 (- \frac{1}{( x + 4 ) ^{2}} \cdot 1) : - \frac{7}{( x + 4 ) ^{2}}

= - \frac{7}{( x + 4 ) ^{2}}

d x - e^{3 x} d y = 0

\frac{\partial}{\partial x} (x^{6 y})

\frac{d}{d x} (x^{2} 6 x - 1)

\int_{b}^{d} \frac{1}{r} d r

f (x) = 7 x^{3} + 5 x, at x = 7

What is the derivative of 7/(x+4) ?
The derivative of 7/(x+4) is -7/((x+4)^2)
What is the first derivative of 7/(x+4) ?
The first derivative of 7/(x+4) is -7/((x+4)^2)