What is the derivative of 2/(2x-3) ?

The derivative of 2/(2x-3) is -4/((2x-3)^2)

What is the first derivative of 2/(2x-3) ?

The first derivative of 2/(2x-3) is -4/((2x-3)^2)

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derivative of

\frac{2}{2 x - 3}

- \frac{4}{( 2 x - 3 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{2}{2 x - 3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{1}{2 x - 3})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d x} ((2 x - 3)^{- 1})

Apply the chain rule:

- \frac{1}{( 2 x - 3 ) ^{2}} \frac{d}{d x} (2 x - 3)

= - \frac{1}{( 2 x - 3 ) ^{2}} \frac{d}{d x} (2 x - 3)

\frac{d}{d x} (2 x - 3) = 2

= 2 (- \frac{1}{( 2 x - 3 ) ^{2}} \cdot 2)

Simplify

2 (- \frac{1}{( 2 x - 3 ) ^{2}} \cdot 2) : - \frac{4}{( 2 x - 3 ) ^{2}}

= - \frac{4}{( 2 x - 3 ) ^{2}}

\int cos (x) sin (k x) d x

0.0588 s^{1.125}

\int_{0}^{\frac{1}{2}} 4 cos (π x) d x

\int x \cdot \frac{1}{x ^{2}} d x

x \to - 3 lim (- 2 x^{3})

What is the derivative of 2/(2x-3) ?
The derivative of 2/(2x-3) is -4/((2x-3)^2)
What is the first derivative of 2/(2x-3) ?
The first derivative of 2/(2x-3) is -4/((2x-3)^2)