What is the limit as x approaches-infinity of (8x^3)/(9x^4) ?

The limit as x approaches-infinity of (8x^3)/(9x^4) is 0

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limit as x approaches-infinity of (8x^3)/(9x^4)

x \to - \infty lim (\frac{8 x ^{3}}{9 x ^{4}})

0

Solution steps

x \to - \infty lim (\frac{8 x ^{3}}{9 x ^{4}})

Simplify

\frac{8 x ^{3}}{9 x ^{4}} : \frac{8}{9 x}

= x \to - \infty lim (\frac{8}{9 x})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= \frac{8}{9} \cdot x \to - \infty lim (\frac{1}{x})

x \to a lim [\frac{f ( x )}{g ( x )}] = \frac{lim _{x \to a} f ( x )}{lim _{x \to a} g ( x )}, x \to a lim g (x) \neq = 0

With the exception of indeterminate form

= \frac{8}{9} \cdot \frac{lim _{x \to - \infty} ( 1 )}{lim _{x \to - \infty} ( x )}

x \to - \infty lim (1) = 1

x \to - \infty lim (x) = - \infty

= \frac{8}{9} \cdot \frac{1}{- \infty}

Simplify

\frac{8}{9} \cdot \frac{1}{- \infty} : 0

= 0

\int - cos (x) 2 x d x

x^{2} + \frac{16}{x}

\frac{d}{d x} (\frac{x - 5}{3 x - 4})

\frac{d}{d x} (- \frac{ln ( 2 )}{x ( x + ln ( 2 ) )})

\frac{d x}{d y} = - x^{2} + 7 x - 8

What is the limit as x approaches-infinity of (8x^3)/(9x^4) ?
The limit as x approaches-infinity of (8x^3)/(9x^4) is 0