What is the tangent of f(x)=6sin(x)+4cos(x),\at x=0 ?

The tangent of f(x)=6sin(x)+4cos(x),\at x=0 is y=6x+4

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tangent of f(x)=6sin(x)+4cos(x),\at x=0

tangent of

f (x) = 6 sin (x) + 4 cos (x), at x = 0

y = 6 x + 4

Solution steps

Find the tangent point:

(0, 4)

Find the slope of

f (x) = 6 sin (x) + 4 cos (x) : \frac{df ( x )}{d x} = 6 cos (x) - 4 sin (x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 6

Find the line with slope m=

6

and passing through

(0, 4) : y = 6 x + 4

y = 6 x + 4

\int \frac{( arctan ( x ) ) ^{7}}{1 + x ^{2}} d x

x \to 1 lim (\frac{1 - x}{x - 1})

f (x) = 5 x^{4} e^{x} + e^{x} x^{5}

4 + x^{2} + 4 x^{4}, - 3

f (t) = sin (4 t)

What is the tangent of f(x)=6sin(x)+4cos(x),\at x=0 ?
The tangent of f(x)=6sin(x)+4cos(x),\at x=0 is y=6x+4