What is the derivative of (3x^{6x}) ?

The derivative of (3x^{6x}) is 2ln(3)*3^{6x+1}x^{6x}+2*3^{1+6x}x^{6x}(ln(x)+1)

What is the first derivative of (3x^{6x}) ?

The first derivative of (3x^{6x}) is 2ln(3)*3^{6x+1}x^{6x}+2*3^{1+6x}x^{6x}(ln(x)+1)

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\frac{d}{d x} ((3 x)^{6 x})

2 ln (3) \cdot 3^{6 x + 1} x^{6 x} + 2 \cdot 3^{1 + 6 x} x^{6 x} (ln (x) + 1)

Solution steps

\frac{d}{d x} ((3 x)^{6 x})

Simplify

(3 x)^{6 x} : 72 9^{x} x^{6 x}

= \frac{d}{d x} (72 9^{x} x^{6 x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 72 9^{x}, g = x^{6 x}

= \frac{d}{d x} (72 9^{x}) x^{6 x} + \frac{d}{d x} (x^{6 x}) 72 9^{x}

\frac{d}{d x} (72 9^{x}) = 2 ln (3) \cdot 3^{6 x + 1}

\frac{d}{d x} (x^{6 x}) = 6 x^{6 x} (ln (x) + 1)

= 2 ln (3) \cdot 3^{6 x + 1} x^{6 x} + 6 x^{6 x} (ln (x) + 1) \cdot 72 9^{x}

6 x^{6 x} (ln (x) + 1) \cdot 72 9^{x} = 2 \cdot 3^{1 + 6 x} x^{6 x} (ln (x) + 1)

= 2 ln (3) \cdot 3^{6 x + 1} x^{6 x} + 2 \cdot 3^{1 + 6 x} x^{6 x} (ln (x) + 1)

x \to 0 lim (x^{2} cot (x))

y - 2 y^{^{'}} = 0

\int - 2 y cos (y) d y

y = tan (5 x), y = 2 sin (5 x)

x \to - 1 lim (8 x^{4} - 3 x^{3} + 5 x)

What is the derivative of (3x^{6x}) ?
The derivative of (3x^{6x}) is 2ln(3)*3^{6x+1}x^{6x}+2*3^{1+6x}x^{6x}(ln(x)+1)
What is the first derivative of (3x^{6x}) ?
The first derivative of (3x^{6x}) is 2ln(3)*3^{6x+1}x^{6x}+2*3^{1+6x}x^{6x}(ln(x)+1)