What is expand-8(64e^{-4x^2}x^3-24e^{-4x^2}x) ?

The solution to expand-8(64e^{-4x^2}x^3-24e^{-4x^2}x) is -512e^{-4x^2}x^3+192e^{-4x^2}x

expand-8(64e^{-4x^2}x^3-24e^{-4x^2}x)

expand

- 8 (64 e^{- 4 x^{2}} x^{3} - 24 e^{- 4 x^{2}} x)

- 512 e^{- 4 x^{2}} x^{3} + 192 e^{- 4 x^{2}} x

Solution steps

- 8 (64 e^{- 4 x^{2}} x^{3} - 24 e^{- 4 x^{2}} x)

Apply the distributive law:

a (b - c) = ab - a c

a = - 8, b = 64 e^{- 4 x^{2}} x^{3}, c = 24 e^{- 4 x^{2}} x

= - 8 \cdot 64 e^{- 4 x^{2}} x^{3} - (- 8) \cdot 24 e^{- 4 x^{2}} x

Apply minus-plus rules

- (- a) = a

= - 8 \cdot 64 e^{- 4 x^{2}} x^{3} + 8 \cdot 24 e^{- 4 x^{2}} x

Simplify

- 8 \cdot 64 e^{- 4 x^{2}} x^{3} + 8 \cdot 24 e^{- 4 x^{2}} x : - 512 e^{- 4 x^{2}} x^{3} + 192 e^{- 4 x^{2}} x

= - 512 e^{- 4 x^{2}} x^{3} + 192 e^{- 4 x^{2}} x

\int e^{- s t} (2 t + 1) d t

\frac{d}{d x} (50 e^{- 0.5 x} - (\frac{5}{x}))

\frac{\partial}{\partial x} (x + e^{4 y})

\int \frac{( 3 x + 4 )}{( x ^{2} + 4 ) ( 3 - x )} d x

- (x)^{2} 1

What is expand-8(64e^{-4x^2}x^3-24e^{-4x^2}x) ?
The solution to expand-8(64e^{-4x^2}x^3-24e^{-4x^2}x) is -512e^{-4x^2}x^3+192e^{-4x^2}x