What is the d/(dt)(cos(t)-sin(t)) ?

The d/(dt)(cos(t)-sin(t)) is -sin(t)-cos(t)

What is the first d/(dt)(cos(t)-sin(t)) ?

The first d/(dt)(cos(t)-sin(t)) is -sin(t)-cos(t)

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\frac{d}{d t} (cos (t) - sin (t))

- sin (t) - cos (t)

Solution steps

\frac{d}{d t} (cos (t) - sin (t))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (cos (t)) - \frac{d}{d t} (sin (t))

\frac{d}{d t} (cos (t)) = - sin (t)

\frac{d}{d t} (sin (t)) = cos (t)

= - sin (t) - cos (t)

\int + \frac{e ^{2 x}}{1 + e ^{2 x}} d x

f (x) = 4 x^{2} - 4 x + 1, at x = 1

\frac{\partial}{\partial x} (x sin (x + y) - cos (x + y))

y^{^{'}} = y^{4} \cdot (4 x^{2} + x)

(7, 4), (1, - 2)

What is the d/(dt)(cos(t)-sin(t)) ?
The d/(dt)(cos(t)-sin(t)) is -sin(t)-cos(t)
What is the first d/(dt)(cos(t)-sin(t)) ?
The first d/(dt)(cos(t)-sin(t)) is -sin(t)-cos(t)