What is the integral from 0 to 0.6 of 600x ?

The integral from 0 to 0.6 of 600x is 108

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integral from 0 to 0.6 of 600x

\int_{0}^{0.6} 600 x d x

108

Solution steps

\int_{0}^{0.6} 600 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 600 \cdot \int_{0}^{0.6} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{0.6}

= 600 [\frac{x ^{2}}{2}]_{0}^{0.6}

Simplify

= 600 [0.5 x^{2}]_{0}^{0.6}

Compute the boundaries:

0.18

= 600 \cdot 0.18

Simplify

= 108

\int \frac{1}{500} e^{- \frac{1}{500} t} d t

\frac{\partial}{\partial y} (8 x + 6 x^{2} y + 2 y^{2})

\frac{1}{8}

\int sin (4 x) cos (5 x) d x

\int_{1}^{2} (2 - x)^{\frac{- 2}{3}} d x

What is the integral from 0 to 0.6 of 600x ?
The integral from 0 to 0.6 of 600x is 108