What is the integral from 4 to 9 of 6sqrt(x) ?

The integral from 4 to 9 of 6sqrt(x) is 76

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integral from 4 to 9 of 6sqrt(x)

\int_{4}^{9} 6 x d x

76

Solution steps

\int_{4}^{9} 6 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int_{4}^{9} x d x

Apply the Power Rule

: [\frac{2}{3} x^{\frac{3}{2}}]_{4}^{9}

= 6 [\frac{2}{3} x^{\frac{3}{2}}]_{4}^{9}

Compute the boundaries:

\frac{38}{3}

= 6 \cdot \frac{38}{3}

Simplify

= 76

x^{5} + x^{2} y^{3} = 0

\int \frac{( ln ( x ^{7} ) )}{x} d x

y^{^{'}} = \frac{3 x ^{2} - e ^{x}}{2 y - 5}

\frac{\partial}{\partial x} (x^{2} + y^{2} + 1)

y = 4 ln (cos (x))

What is the integral from 4 to 9 of 6sqrt(x) ?
The integral from 4 to 9 of 6sqrt(x) is 76