What is the tangent of cos(3x) ?

The tangent of cos(3x) is y=-sin(3a_{0})*3x+cos(3a_{0})+3a_{0}sin(3a_{0})

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tangent of cos(3x)

tangent of

cos (3 x)

y = - sin (3 a_{0}) \cdot 3 x + cos (3 a_{0}) + 3 a_{0} sin (3 a_{0})

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, cos (3 a_{0}))

Find the slope of

y = cos (3 x) : \frac{d y}{d x} = - sin (3 x) \cdot 3

Compute the slope of

y = cos (3 x)

x = a_{0} : m = - sin (3 a_{0}) \cdot 3

Find the line with slope m=

- sin (3 a_{0}) 3

and passing through

(a_{0}, cos (3 a_{0})) : y = - sin (3 a_{0}) \cdot 3 x + cos (3 a_{0}) + 3 a_{0} sin (3 a_{0})

y = - sin (3 a_{0}) \cdot 3 x + cos (3 a_{0}) + 3 a_{0} sin (3 a_{0})

y = \frac{7 x - 1}{8 x + 3}

\frac{\partial}{\partial x} (x e^{3 y})

\frac{d}{d x} (2 x^{2} (x - 4 x^{3}))

n = 0 \sum \infty 2 (- \frac{2}{3})

\frac{d x}{d t} + t^{3} x^{5} + \frac{x}{t} = 0

What is the tangent of cos(3x) ?
The tangent of cos(3x) is y=-sin(3a_{0})*3x+cos(3a_{0})+3a_{0}sin(3a_{0})