What is the derivative of f(x)=(x^2-9)/(x^2+3x) ?

The derivative of f(x)=(x^2-9)/(x^2+3x) is 3/(x^2)

What is the first derivative of f(x)=(x^2-9)/(x^2+3x) ?

The first derivative of f(x)=(x^2-9)/(x^2+3x) is 3/(x^2)

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derivative of

f (x) = \frac{x ^{2} - 9}{x ^{2} + 3 x}

\frac{3}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 9}{x ^{2} + 3 x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} - 9 ) ( x ^{2} + 3 x ) - \frac{d}{d x} ( x ^{2} + 3 x ) ( x ^{2} - 9 )}{( x ^{2} + 3 x ) ^{2}}

\frac{d}{d x} (x^{2} - 9) = 2 x

\frac{d}{d x} (x^{2} + 3 x) = 2 x + 3

= \frac{2 x ( x ^{2} + 3 x ) - ( 2 x + 3 ) ( x ^{2} - 9 )}{( x ^{2} + 3 x ) ^{2}}

Simplify

\frac{2 x ( x ^{2} + 3 x ) - ( 2 x + 3 ) ( x ^{2} - 9 )}{( x ^{2} + 3 x ) ^{2}} : \frac{3}{x ^{2}}

= \frac{3}{x ^{2}}

y = x, y = 2 x 100 - x^{2}

f (x) = 186.7

y^{^{''}} - y^{^{'}} + y = 3 sin (t) - 15 e^{2 t}

\frac{d}{d x} ((9 x - 1)^{- 2})

\int \frac{x ^{2}}{e ^{x + 1}} d x

What is the derivative of f(x)=(x^2-9)/(x^2+3x) ?
The derivative of f(x)=(x^2-9)/(x^2+3x) is 3/(x^2)
What is the first derivative of f(x)=(x^2-9)/(x^2+3x) ?
The first derivative of f(x)=(x^2-9)/(x^2+3x) is 3/(x^2)