What is the derivative of 1-sin^2(x) ?

The derivative of 1-sin^2(x) is -sin(2x)

What is the first derivative of 1-sin^2(x) ?

The first derivative of 1-sin^2(x) is -sin(2x)

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derivative of

1 - sin^{2} (x)

- sin (2 x)

Solution steps

\frac{d}{d x} (1 - sin^{2} (x))

Simplify

1 - sin^{2} (x) : cos^{2} (x)

= \frac{d}{d x} (cos^{2} (x))

Apply the chain rule:

2 cos (x) \frac{d}{d x} (cos (x))

= 2 cos (x) \frac{d}{d x} (cos (x))

\frac{d}{d x} (cos (x)) = - sin (x)

= 2 cos (x) (- sin (x))

Simplify

2 cos (x) (- sin (x)) : - sin (2 x)

= - sin (2 x)

\int \frac{13 x e ^{2 x}}{( 1 + 2 x ) ^{2}} d x

\frac{\partial}{\partial x} (3 sin (x))

\int 4 x^{2} - sin (x) + 2 d x

(1 - \frac{4}{x + 2})^{3}

5 tan (x), at x = \frac{π}{3}

What is the derivative of 1-sin^2(x) ?
The derivative of 1-sin^2(x) is -sin(2x)
What is the first derivative of 1-sin^2(x) ?
The first derivative of 1-sin^2(x) is -sin(2x)