What is the first derivative of 9t ?

The first derivative of 9t is 9

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derivative of 9t

derivative of

9 t

9

Solution steps

\frac{d}{d t} (9 t)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d t}{d t}

Apply the common derivative:

\frac{d t}{d t} = 1

= 9 \cdot 1

Simplify

= 9

\frac{d}{d x} (16 x^{\frac{3}{2}})

\frac{d}{d x} (2 x^{\frac{3}{4}} + 4 x^{- \frac{1}{4}})

\frac{3 x}{x ^{2} - 6} (3.3)

\int \frac{1}{2 - x} d x

y^{2} = \frac{1}{8} x, y = 8 x^{2}