What is the derivative of (x^2-3x^2) ?

The derivative of (x^2-3x^2) is 2(x^2-3x)(2x-3)

What is the first derivative of (x^2-3x^2) ?

The first derivative of (x^2-3x^2) is 2(x^2-3x)(2x-3)

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\frac{d}{d x} ((x^{2} - 3 x)^{2})

2 (x^{2} - 3 x) (2 x - 3)

Solution steps

\frac{d}{d x} ((x^{2} - 3 x)^{2})

Apply the chain rule:

2 (x^{2} - 3 x) \frac{d}{d x} (x^{2} - 3 x)

= 2 (x^{2} - 3 x) \frac{d}{d x} (x^{2} - 3 x)

\frac{d}{d x} (x^{2} - 3 x) = 2 x - 3

= 2 (x^{2} - 3 x) (2 x - 3)

\int_{1}^{\infty} \frac{4}{1 + x ^{2}} d x

\int \frac{1}{2 cos ( x )} d x

\frac{110}{x ^{12}}

x^{^{''}} = - 9 x

\frac{d}{d x} ((\frac{2 x ^{2} - x ^{- 2}}{4 x + 3})^{\frac{3}{4}})

What is the derivative of (x^2-3x^2) ?
The derivative of (x^2-3x^2) is 2(x^2-3x)(2x-3)
What is the first derivative of (x^2-3x^2) ?
The first derivative of (x^2-3x^2) is 2(x^2-3x)(2x-3)