What is taylor 1/x ,4 ?

The answer to taylor 1/x ,4 is 1/4-1/16 (x-4)+1/64 (x-4)^2-1/256 (x-4)^3+1/1024 (x-4)^4+\ldots

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

taylor 1/x ,4

taylor

\frac{1}{x}, 4

\frac{1}{4} - \frac{1}{16} (x - 4) + \frac{1}{64} (x - 4)^{2} - \frac{1}{256} (x - 4)^{3} + \frac{1}{1024} (x - 4)^{4} + \dots

Solution steps

Apply the Taylor Formula

= \frac{1}{4} + \frac{\frac{d}{d x} ( \frac{1}{x} ) ( 4 )}{1 !} (x - 4) + \frac{\frac{d ^{2}}{d x ^{2}} ( \frac{1}{x} ) ( 4 )}{2 !} (x - 4)^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( \frac{1}{x} ) ( 4 )}{3 !} (x - 4)^{3} + \dots

Evaluate Derivatives

= \frac{1}{4} + \frac{- \frac{1}{16}}{1 !} (x - 4) + \frac{\frac{1}{32}}{2 !} (x - 4)^{2} + \frac{- \frac{3}{128}}{3 !} (x - 4)^{3} + \frac{\frac{3}{128}}{4 !} (x - 4)^{4} + \dots

Refine

= \frac{1}{4} - \frac{1}{16} (x - 4) + \frac{1}{64} (x - 4)^{2} - \frac{1}{256} (x - 4)^{3} + \frac{1}{1024} (x - 4)^{4} + \dots

\int e^{8 x - 9} d x

f (x) = ln (x), at x = e^{- 7}

\int \frac{1}{( \frac{1}{3} x - 8 ) ^{5}} d x

\frac{d ^{2}}{d x ^{2}} (3 x^{2} + 4 x)

\frac{\partial}{\partial x} (x e^{3 x y})

What is taylor 1/x ,4 ?
The answer to taylor 1/x ,4 is 1/4-1/16 (x-4)+1/64 (x-4)^2-1/256 (x-4)^3+1/1024 (x-4)^4+\ldots