What is the integral of 2/(3\sqrt[3]{x)} ?

The integral of 2/(3\sqrt[3]{x)} is x^{2/3}+C

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integral of 2/(3\sqrt[3]{x)}

x^{\frac{2}{3}} + C

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

Apply the Power Rule

: \frac{3}{2} x^{\frac{2}{3}}

= \frac{2}{3} \cdot \frac{3}{2} x^{\frac{2}{3}}

Simplify

\frac{2}{3} \cdot \frac{3}{2} x^{\frac{2}{3}} : x^{\frac{2}{3}}

= x^{\frac{2}{3}}

Add a constant to the solution

= x^{\frac{2}{3}} + C

\frac{\partial}{\partial x} (- 4 sin (x))

\frac{d}{d x} (((- 3 x + 1)^{4} - 5)^{3})

\frac{d}{d x} (\frac{( - 2 x - 3 ) ^{7}}{( 4 x + 2 ) ^{4}})

2 - 2 x^{2}

\int \frac{y}{( y ^{2} + 1 ) ^{2}} d y

What is the integral of 2/(3\sqrt[3]{x)} ?
The integral of 2/(3\sqrt[3]{x)} is x^{2/3}+C