What is the derivative of (1/(x^2-5/(x^4))(x+7x^3)) ?

The derivative of (1/(x^2-5/(x^4))(x+7x^3)) is (34)/(x^2)+(15)/(x^4)+7

What is the first derivative of (1/(x^2-5/(x^4))(x+7x^3)) ?

The first derivative of (1/(x^2-5/(x^4))(x+7x^3)) is (34)/(x^2)+(15)/(x^4)+7

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\frac{d}{d x} ((\frac{1}{x ^{2}} - \frac{5}{x ^{4}}) (x + 7 x^{3}))

\frac{34}{x ^{2}} + \frac{15}{x ^{4}} + 7

Solution steps

\frac{d}{d x} ((\frac{1}{x ^{2}} - \frac{5}{x ^{4}}) (x + 7 x^{3}))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = \frac{1}{x ^{2}} - \frac{5}{x ^{4}}, g = x + 7 x^{3}

= \frac{d}{d x} (\frac{1}{x ^{2}} - \frac{5}{x ^{4}}) (x + 7 x^{3}) + \frac{d}{d x} (x + 7 x^{3}) (\frac{1}{x ^{2}} - \frac{5}{x ^{4}})

\frac{d}{d x} (\frac{1}{x ^{2}} - \frac{5}{x ^{4}}) = - \frac{2}{x ^{3}} + \frac{20}{x ^{5}}

\frac{d}{d x} (x + 7 x^{3}) = 1 + 21 x^{2}

= (- \frac{2}{x ^{3}} + \frac{20}{x ^{5}}) (x + 7 x^{3}) + (1 + 21 x^{2}) (\frac{1}{x ^{2}} - \frac{5}{x ^{4}})

Simplify

(- \frac{2}{x ^{3}} + \frac{20}{x ^{5}}) (x + 7 x^{3}) + (1 + 21 x^{2}) (\frac{1}{x ^{2}} - \frac{5}{x ^{4}}) : \frac{34}{x ^{2}} + \frac{15}{x ^{4}} + 7

= \frac{34}{x ^{2}} + \frac{15}{x ^{4}} + 7

\int_{3}^{4} 5 lo g_{6} (t) d t

\int \frac{1}{3 - y} d y

x \to 4 lim (\frac{x ^{2} - 2}{x - 4})

\frac{d y}{d x} - y = 1

\int 3 cos (x) + e^{- x} + 4 d x

What is the derivative of (1/(x^2-5/(x^4))(x+7x^3)) ?
The derivative of (1/(x^2-5/(x^4))(x+7x^3)) is (34)/(x^2)+(15)/(x^4)+7
What is the first derivative of (1/(x^2-5/(x^4))(x+7x^3)) ?
The first derivative of (1/(x^2-5/(x^4))(x+7x^3)) is (34)/(x^2)+(15)/(x^4)+7