What is the integral from 1 to 2 of 1/(x^6) ?

The integral from 1 to 2 of 1/(x^6) is 31/160

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integral from 1 to 2 of 1/(x^6)

\int_{1}^{2} \frac{1}{x ^{6}} d x

\frac{31}{160}

Decimal

0.19375

Solution steps

\int_{1}^{2} \frac{1}{x ^{6}} d x

Apply the Power Rule

: [- \frac{1}{5 x ^{5}}]_{1}^{2}

= [- \frac{1}{5 x ^{5}}]_{1}^{2}

Compute the boundaries:

\frac{31}{160}

= \frac{31}{160}

\int \frac{2 x + 1}{x ^{2}} d x

\frac{d}{d x} ((6 x)^{- 5})

\frac{d}{d x} (x + \frac{3}{x})

y^{^{''}} + 25 y = t sin (5 t)

(x^{2} - x y) d x + x^{2} d y = 0

What is the integral from 1 to 2 of 1/(x^6) ?
The integral from 1 to 2 of 1/(x^6) is 31/160