What is the limit as x approaches 3 of 4x+|x-3| ?

The limit as x approaches 3 of 4x+|x-3| is 12

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limit as x approaches 3 of 4x+|x-3|

x \to 3 lim (4 x + ∣ x - 3 ∣)

12

Solution steps

x \to 3 lim (4 x + ∣ x - 3 ∣)

Plug in the value

x = 3

= 4 \cdot 3 + ∣ 3 - 3 ∣

Simplify

4 \cdot 3 + ∣ 3 - 3 ∣ : 12

= 12

\frac{1}{4 - x}

\int θ cos^{2} (θ) d θ

y = (\frac{x}{7} + 9)^{\frac{3}{2}}

\frac{d}{d x} (\frac{x - 1}{x ^{2} + x - 2})

\frac{d y}{d x} = x + x y

What is the limit as x approaches 3 of 4x+|x-3| ?
The limit as x approaches 3 of 4x+|x-3| is 12