What is area y=e^x,y=e^{-x},[0,1] ?

The answer to area y=e^x,y=e^{-x},[0,1] is (e^2+1)/e-2

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area y=e^x,y=e^{-x},[0,1]

area

y = e^{x}, y = e^{- x}, [0, 1]

\frac{e ^{2} + 1}{e} - 2

Decimal

1.08616 \dots

Solution steps

Apply the area formula:

\int_{0}^{1} e^{x} - e^{- x} d x

Solve

\int_{0}^{1} e^{x} - e^{- x} d x : \frac{e ^{2} + 1}{e} - 2

The area is:

= \frac{e ^{2} + 1}{e} - 2

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\int_{0}^{1} \frac{1}{4 + x ^{2}} d x

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What is area y=e^x,y=e^{-x},[0,1] ?
The answer to area y=e^x,y=e^{-x},[0,1] is (e^2+1)/e-2