What is the sum from n=1 to infinity of 3/((-2)^n) ?

The sum from n=1 to infinity of 3/((-2)^n) is converges

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sum from n=1 to infinity of 3/((-2)^n)

n = 1 \sum \infty \frac{3}{( - 2 ) ^{n}}

converges

Solution steps

n = 1 \sum \infty \frac{3}{( - 2 ) ^{n}}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 3 \cdot n = 1 \sum \infty \frac{1}{( - 2 ) ^{n}}

Apply Series Ratio Test:

converges

= 3 converges

= converges

\int_{0}^{\infty} \frac{1}{5 + x} d x

f (x) = x^{2}

5 arcsin (\frac{x - 1}{x + 1})

y = \frac{2 x ^{2} + 8 x + 4}{x}

x \to \infty + lim (x^{0})

What is the sum from n=1 to infinity of 3/((-2)^n) ?
The sum from n=1 to infinity of 3/((-2)^n) is converges