What is (d^2)/(dx^2)(2^{x^2+1}) ?

The answer to (d^2)/(dx^2)(2^{x^2+1}) is ln(2)(ln(2)*2^{x^2+3}x^2+2^{x^2+2})

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(d^2)/(dx^2)(2^{x^2+1})

\frac{d ^{2}}{d x ^{2}} (2^{x^{2} + 1})

ln (2) (ln (2) \cdot 2^{x^{2} + 3} x^{2} + 2^{x^{2} + 2})

Solution steps

\frac{d ^{2}}{d x ^{2}} (2^{x^{2} + 1})

\frac{d}{d x} (2^{x^{2} + 1}) = ln (2) \cdot 2^{x^{2} + 2} x

= \frac{d}{d x} (ln (2) \cdot 2^{x^{2} + 2} x)

\frac{d}{d x} (ln (2) \cdot 2^{x^{2} + 2} x) = ln (2) (ln (2) \cdot 2^{x^{2} + 3} x^{2} + 2^{x^{2} + 2})

= ln (2) (ln (2) \cdot 2^{x^{2} + 3} x^{2} + 2^{x^{2} + 2})

\frac{d y}{d x} = e^{5 y}

\frac{d}{d x} (e^{- 2 x} sin (x))

x \to - 1 lim (\frac{∣ x ∣}{x})

\frac{d P}{d t} = P (\frac{1}{t} - P)

x \to 2 lim (x^{2} + x)

What is (d^2)/(dx^2)(2^{x^2+1}) ?
The answer to (d^2)/(dx^2)(2^{x^2+1}) is ln(2)(ln(2)*2^{x^2+3}x^2+2^{x^2+2})