What is the derivative of f(x)=x^3-3x+1 ?

The derivative of f(x)=x^3-3x+1 is 3x^2-3

What is the first derivative of f(x)=x^3-3x+1 ?

The first derivative of f(x)=x^3-3x+1 is 3x^2-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = x^{3} - 3 x + 1

3 x^{2} - 3

Solution steps

\frac{d}{d x} (x^{3} - 3 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (3 x) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (1) = 0

= 3 x^{2} - 3 + 0

Simplify

= 3 x^{2} - 3

x = 36 - y^{2}, x = y^{2} - 36

\int t - cos (t) d t

\frac{d}{d x} (\frac{3 x ^{2} - 18 x + 25}{x ^{2} - 6 x + 8})

\int \frac{4 x - 2}{( 4 x ^{2} - 4 x + 2 ) ^{4}} d x

\frac{1 - e ^{- 2 s}}{6 s ^{2}}

What is the derivative of f(x)=x^3-3x+1 ?
The derivative of f(x)=x^3-3x+1 is 3x^2-3
What is the first derivative of f(x)=x^3-3x+1 ?
The first derivative of f(x)=x^3-3x+1 is 3x^2-3