What is inverse oflaplace f(s)=s-3(s^2+4s+13) ?

The answer to inverse oflaplace f(s)=s-3(s^2+4s+13) is No solution in terms of standard functions

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inverse oflaplace f(s)=s-3(s^2+4s+13)

inverse laplace

f (s) = s - 3 (s^{2} + 4 s + 13)

No solution in terms of standard functions

Solution steps

L^{- 1} {s - 3 (s^{2} + 4 s + 13)}

= No solution in terms of standard functions

y^{2} = 4 x, y^{2} = \frac{4}{x}

n = 1 \sum \infty \frac{( 2 n ) !}{5 ^{n} ( n ! ) ^{2}}

x \to 0 lim (\frac{e ^{x^{5}} - 1}{x})

\frac{\partial}{\partial x} (\frac{x + 3}{y + 2})

\int_{2}^{r} \frac{1}{x ln ( x )} d x

What is inverse oflaplace f(s)=s-3(s^2+4s+13) ?
The answer to inverse oflaplace f(s)=s-3(s^2+4s+13) is No solution in terms of standard functions