What is the d/(dt)(1/((t+1)^2)) ?

The d/(dt)(1/((t+1)^2)) is -2/((t+1)^3)

What is the first d/(dt)(1/((t+1)^2)) ?

The first d/(dt)(1/((t+1)^2)) is -2/((t+1)^3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d t} (\frac{1}{( t + 1 ) ^{2}})

- \frac{2}{( t + 1 ) ^{3}}

Solution steps

\frac{d}{d t} (\frac{1}{( t + 1 ) ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d t} ((t + 1)^{- 2})

Apply the chain rule:

- \frac{2}{( t + 1 ) ^{3}} \frac{d}{d t} (t + 1)

= - \frac{2}{( t + 1 ) ^{3}} \frac{d}{d t} (t + 1)

\frac{d}{d t} (t + 1) = 1

= - \frac{2}{( t + 1 ) ^{3}} \cdot 1

Simplify

= - \frac{2}{( t + 1 ) ^{3}}

\int 3 x y^{2} d y

\frac{\partial}{\partial x} (e^{e^{y} (1 + e^{x}) - 2})

x^{2} - 2, - (x - 1)^{2} + 3

\int x^{4} (3 x^{5} - 1)^{6} d x

x d y - y d x = x^{2} + y^{2} d x

What is the d/(dt)(1/((t+1)^2)) ?
The d/(dt)(1/((t+1)^2)) is -2/((t+1)^3)
What is the first d/(dt)(1/((t+1)^2)) ?
The first d/(dt)(1/((t+1)^2)) is -2/((t+1)^3)