What is the derivative of-1/((1-x^2)) ?

The derivative of-1/((1-x^2)) is -2/((1-x)^3)

What is the first derivative of-1/((1-x^2)) ?

The first derivative of-1/((1-x^2)) is -2/((1-x)^3)

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\frac{d}{d x} (- \frac{1}{( 1 - x ) ^{2}})

- \frac{2}{( 1 - x ) ^{3}}

Solution steps

\frac{d}{d x} (- \frac{1}{( 1 - x ) ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (\frac{1}{( 1 - x ) ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - \frac{d}{d x} ((1 - x)^{- 2})

Apply the chain rule:

- \frac{2}{( 1 - x ) ^{3}} \frac{d}{d x} (1 - x)

= - \frac{2}{( 1 - x ) ^{3}} \frac{d}{d x} (1 - x)

\frac{d}{d x} (1 - x) = - 1

= - (- \frac{2}{( 1 - x ) ^{3}} (- 1))

Simplify

= - \frac{2}{( 1 - x ) ^{3}}

y = arctan (4 t)

x \to 2 + lim (\frac{4 x}{x - 2})

x y^{^{'}} - 2 y = x^{2} - 2 x - 1

\frac{\partial}{\partial x} (cot (x y))

\frac{1}{( 1 - x )}, 2

What is the derivative of-1/((1-x^2)) ?
The derivative of-1/((1-x^2)) is -2/((1-x)^3)
What is the first derivative of-1/((1-x^2)) ?
The first derivative of-1/((1-x^2)) is -2/((1-x)^3)