What is the derivative of 2*e^{x^2-4x} ?

The derivative of 2*e^{x^2-4x} is 2e^{x^2-4x}(2x-4)

What is the first derivative of 2*e^{x^2-4x} ?

The first derivative of 2*e^{x^2-4x} is 2e^{x^2-4x}(2x-4)

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derivative of

2 \cdot e^{x^{2} - 4 x}

2 e^{x^{2} - 4 x} (2 x - 4)

Solution steps

\frac{d}{d x} (2 e^{x^{2} - 4 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (e^{x^{2} - 4 x})

Apply the chain rule:

e^{x^{2} - 4 x} \frac{d}{d x} (x^{2} - 4 x)

= e^{x^{2} - 4 x} \frac{d}{d x} (x^{2} - 4 x)

\frac{d}{d x} (x^{2} - 4 x) = 2 x - 4

= 2 e^{x^{2} - 4 x} (2 x - 4)

\int 2 x - 5 d x

\int 8 x ln (3 x) d x

\frac{d}{d x} (x ln (x^{2} + 4) + 4 arctan (\frac{x}{2}) - 2 x)

\int arctan (2 y) d y

\frac{d}{d x} (cos (3 x))

What is the derivative of 2*e^{x^2-4x} ?
The derivative of 2*e^{x^2-4x} is 2e^{x^2-4x}(2x-4)
What is the first derivative of 2*e^{x^2-4x} ?
The first derivative of 2*e^{x^2-4x} is 2e^{x^2-4x}(2x-4)