What is the derivative of 5cos(t) ?

The derivative of 5cos(t) is -5sin(t)

What is the first derivative of 5cos(t) ?

The first derivative of 5cos(t) is -5sin(t)

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derivative of

5 cos (t)

- 5 sin (t)

Solution steps

\frac{d}{d t} (5 cos (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d t} (cos (t))

Apply the common derivative:

\frac{d}{d t} (cos (t)) = - sin (t)

= 5 (- sin (t))

Simplify

= - 5 sin (t)

\frac{d}{d x} (3 e^{x} sin (x))

y^{^{''}} + 16 y = - 16 sec^{2} (4 x)

\frac{\partial}{\partial x} (\frac{c + 1}{c + x})

\frac{d}{d x} (\frac{x - 3}{x + 2})

\frac{d y}{d x} = 3 x y

What is the derivative of 5cos(t) ?
The derivative of 5cos(t) is -5sin(t)
What is the first derivative of 5cos(t) ?
The first derivative of 5cos(t) is -5sin(t)