What is the limit as x approaches 0 of-2x-h+4 ?

The limit as x approaches 0 of-2x-h+4 is -h+4

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limit as x approaches 0 of-2x-h+4

x \to 0 lim (- 2 x - h + 4)

- h + 4

Solution steps

x \to 0 lim (- 2 x - h + 4)

Plug in the value

x = 0

= - 2 \cdot 0 - h + 4

Simplify

= - h + 4

n = 1 \sum \infty (- 1)^{n + 1} (\frac{3}{2 ^{n}})

\int \frac{1}{sin ( 2 y ) cos ( 2 y )} d y

\frac{d}{d x} (4 - e^{2 x})

\int (1 - cos (2 t)) (cos (t)) t d t

n = 0 \sum \infty n^{2} e^{- 7 n}

What is the limit as x approaches 0 of-2x-h+4 ?
The limit as x approaches 0 of-2x-h+4 is -h+4