What is the tangent of f(x)=-4x^{1/2}-10,\at x=9 ?

The tangent of f(x)=-4x^{1/2}-10,\at x=9 is y=-2/3 x-16

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tangent of f(x)=-4x^{1/2}-10,\at x=9

tangent of

f (x) = - 4 x^{\frac{1}{2}} - 10, at x = 9

y = - \frac{2}{3} x - 16

Solution steps

Find the tangent point:

(9, - 22)

Find the slope of

f (x) = - 4 x^{\frac{1}{2}} - 10 : \frac{df ( x )}{d x} = - \frac{2}{x ^{\frac{1}{2}}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{2}{3}

Find the line with slope m=

- \frac{2}{3}

and passing through

(9, - 22) : y = - \frac{2}{3} x - 16

y = - \frac{2}{3} x - 16

8 x + 7 cos (x)

f (x) = 2 x^{2} - 5 x + 3, at x = 2

\frac{d}{d t} (\frac{8 t}{8 + t})

\int \frac{1}{t ^{2} - 8 t + 20} d t

x \to 0 lim (\frac{1}{cos ( 3 x )})

What is the tangent of f(x)=-4x^{1/2}-10,\at x=9 ?
The tangent of f(x)=-4x^{1/2}-10,\at x=9 is y=-2/3 x-16