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Popular >

y^{''}+7y^'-8y=0

Solution

y^{^{''}} + 7 y^{^{'}} - 8 y = 0

Solution

y = c_{1} e^{t} + c_{2} e^{- 8 t}

Solution steps

y^{''} (t) + 7 y^{'} (t) - 8 y = 0

Solve linear ODE:

y = c_{1} e^{t} + c_{2} e^{- 8 t}

y = c_{1} e^{t} + c_{2} e^{- 8 t}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^{''}+7y^'-8y=0 ?
The solution for y^{''}+7y^'-8y=0 is y=c_{1}e^t+c_{2}e^{-8t}