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Popular >

y^'-y=10te^{2t}

Solution

y^{^{'}} - y = 10 t e^{2 t}

Solution

y = 10 e^{2 t} (t - 1) + c_{1} e^{t}

Solution steps

y^{'} (t) - y = 10 t e^{2 t}

Solve linear ODE:

y = 10 e^{2 t} (t - 1) + c_{1} e^{t}

y = 10 e^{2 t} (t - 1) + c_{1} e^{t}

Graph

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y^{''}-6y^'-16y=0

y^{^{''}} - 6 y^{^{'}} - 16 y = 0

Frequently Asked Questions (FAQ)

What is the solution for y^'-y=10te^{2t} ?
The solution for y^'-y=10te^{2t} is y=10e^{2t}(t-1)+c_{1}e^t