What is the solution for (dy}{dx}=\frac{(xy+x))/y ?

The solution for (dy}{dx}=\frac{(xy+x))/y is y=-\W(-1/(e^{(-c_{1)+x^2)/2}})-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy}{dx}=\frac{(xy+x))/y

\frac{d y}{d x} = \frac{( x y + x )}{y}

y = - W (- \frac{1}{e ^{\frac{- c _{1} + x ^{2}}{2}}}) - 1

Solution steps

\frac{d y}{d x} = \frac{( x y + x )}{y}

Solve separable ODE:

y = - W (- \frac{1}{e ^{\frac{- c _{1} + x ^{2}}{2}}}) - 1

y = - W (- \frac{1}{e ^{\frac{- c _{1} + x ^{2}}{2}}}) - 1

y^{^{''}} + 2 π y^{^{'}} + π^{2} y = 0

\frac{d y}{d x} = \frac{x ^{2} - 2}{3 y}

\int \frac{( x ^{4} + 2 )}{x ^{3} + 9 x} d x

\int (θ^{8} + sec^{2} (θ)) d θ

sin (x), \frac{2 π}{3}

What is the solution for (dy}{dx}=\frac{(xy+x))/y ?
The solution for (dy}{dx}=\frac{(xy+x))/y is y=-\W(-1/(e^{(-c_{1)+x^2)/2}})-1