What is the solution for f^'=f^3 ?

The solution for f^'=f^3 is f(t)=sqrt(-1/(2(t+c_{1)))},f(t)=-sqrt(-1/(2(t+c_{1)))}

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f^'=f^3

f^{^{'}} = f^{3}

f (t) = - \frac{1}{2 ( t + c _{1} )}, f (t) = - - \frac{1}{2 ( t + c _{1} )}

Solution steps

f^{'} (t) = f (t)^{3}

Solve separable ODE:

f (t) = - \frac{1}{2 ( t + c _{1} )}, f (t) = - - \frac{1}{2 ( t + c _{1} )}

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What is the solution for f^'=f^3 ?
The solution for f^'=f^3 is f(t)=sqrt(-1/(2(t+c_{1)))},f(t)=-sqrt(-1/(2(t+c_{1)))}